Write a COMPLETE and an EFFICIENT C program in which take the values (may contain float values) from the user for two matrices A (order 3x4) and B (order 4x9). No need of validation. No need to display matrices A and B. Your code should compute AxB and store the result in matrix C (of suitable order), and display the result. Finally, your code should store all the even values of matrix C in 1-D array (of suitable order) having name as smart, and display the smart array.

Answer

#include <stdio.h> #include <stdio.h> int main() { // Declare the matrices and the array float A[3][4], B[4][9], C[3][9], smart[27]; // Prompt the user to enter the values for matrices A and B printf("Enter the values for matrix A (3x4):\n"); for (int i = 0; i < 3; i++) { for (int j = 0; j < 4; j++) { scanf("%f", &A[i][j]); } } printf("Enter the values for matrix B (4x9):\n"); for (int i = 0; i < 4; i++) { for (int j = 0; j < 9; j++) { scanf("%f", &B[i][j]); } } // Compute the product AxB and store the result in matrix C for (int i = 0; i < 3; i++) { for (int j = 0; j < 9; j++) { C[i][j] = 0; for (int k = 0; k < 4; k++) { C[i][j] += A[i][k] * B[k][j]; } } } // Store all the even values of matrix C in the array smart int index = 0; for (int i = 0; i < 3; i++) { for (int j = 0; j < 9; j++) { if (C[i][j] % 2 == 0) { smart[index] = C[i][j]; index++; } } } // Display the result printf("Matrix C (3x9) = \n"); for (int i = 0; i < 3; i++) { for (int j = 0; j < 9; j++) { printf("%.2f ", C[i][j]); } printf("\n"); } printf("smart array = \n"); for (int i = 0; i < index; i++) { printf("%.2f ", smart[i]); } printf("\n"); return 0; }

OUTPUT